web.xml 서블릿 선언하기

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
		xmlns="http://java.sun.com/xml/ns/javaee"
		xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
							http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5">
	
	<servlet>
		<servlet-name>dispatcherServlet</servlet-name>
		<servlet-class>com.spring.controller.common.DispatcherServlet</servlet-class>
	</servlet>
	<servlet-mapping>
		<servlet-name>dispatcherServlet</servlet-name>
		<url-pattern>*.do</url-pattern>
	</servlet-mapping>
	
</web-app>